The lowest triplet excited states of (2-substituted) 10-methylphenothiazine were found to be quenched by various electron accepters in polar solvents such as 2-propanol and acetonitrile through electron transfer (ET). The transient absorption and time-resolved EPR spectra indicated that the radical cation of the phenothiazine and radical anions of the accepters were formed as the ET products in moderate to high yields. These free radical ions were formed via two types of intermediates, (i) a triplet contact radical ion pair ((CRIP)-C-3) or a triplet exciplex (3Ex*) and (ii) a triplet solvent-separated radical ion pair ((SSRIP)-S-3). In the quenching by the Br-substituted accepters, a large fraction of 3CRIP (or 3Ex*) was deactivated to the singlet ground states due to the breakdown of the spin-forbiddance by strong spin-orbit coupling. On the other hand, (CRIP)-C-3 (or (3)Ex*) containing no heavy atom was mainly transformed into 3SSRIP by solvation. (SSRIP)-S-3 decayed through either the separation to free ions or the triplet-singlet conversion followed by the spin-allowed backward ET to the ground states. The backward ET rates of (1)SSRIPs were estimated to be greater than or equal to 10(9) s(-1), even when the reaction fell into the deeply inverted region. In 2-propanol, the free ion yields were affected by magnetic fields. The magnitudes of magnetically induced changes strongly depended on the polarity and viscosity of solvents, suggesting that the separation rate of SSRIP should be a crucial factor determining the field dependence of the free ion yields.